发布网友 发布时间:2022-04-26 18:42
共4个回答
热心网友 时间:2022-05-07 17:42
select * from tables1 where keyid not in (select keyid from table2)
热心网友 时间:2022-05-07 19:00
select * from table1
where keyid not in (select keyid from table2)
热心网友 时间:2022-05-07 20:35
select * from table1 except select * from table2
热心网友 时间:2022-05-07 22:26
没能听懂。。。